Factors that 24 are basically the numbers that division it evenly or specifically without leaving any remainder i.e if a number divides 24 with a remainder the zero, then the number is called a factor.

All Factors: 1, 2, 3, 4, 6, 8, 12 and 24.

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Prime factors: 2, 3.Factors in pairs: (1,24), (2,12), (3,8), (4,6),(6,4),(8,3),(12,2).

Prime factorization of 24

Prime factorization is a an approach of “expressing” or finding the provided number as the product of element numbers. If a number occurs an ext than as soon as in element factorization, the is generally expressed in exponential form to do it much more compact.

The prime administrate comes out to be: 2 × 2 × 2 × 3 = 23× 3.

Prime administrate of 24 by Upside-Down division Method

Upside-Down department is among the techniques used to execute the prime factorization of various numbers.

In this method, you will divide a given “composite” number evenly by the number of prime numbers(starting native the smallest) it rotates it gets a prime number.


It is called Upside-Down Division because the prize is flipped upside down.

Here, 24is an even number. So the is indeed divisible through 2 with no remainder.Thus, 2 is its the smallest prime factor.

And we acquire 24÷ 2 = 12. Now find the prime factors of the acquired quotient.

Repeat step 1 and Step 2 until we get a result of element number together the quotient. Here, 12is the quotient.

12÷ 2 = 6. Here, 6 is the quotient.Now discover the prime determinants of the 6.

6÷ 2= 3. Here, 3 is the prime number.

So we can stop theprocess.

So, prime factorization v upside-down division method comes out to be:2× 2× 2× 3 = (2^3 imes 3).

Prime administrate of24 by variable Tree Method

The variable tree method is another an approach for producing the element factorization and also all determinants of a provided number.

To use this an approach for a number x,

Firstly consider two components say a,b the x such that a*b is same to x and also at the very least one of castle (a, b) is a prime aspect say a.

Then think about two determinants of b say c, d such the again at least one of castle is a prime factor. This process is repetitive until both the determinants are element i.e if we acquire both the factors as element at any kind of step, we avoid the process there.

Following is the aspect tree of the provided number.

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Here we can gain the element factorisation of 24 as 2 * 2 * 2 * 3 and the 2 prime factors are 2, 3


What is the amount of the factors of 24?

Sum the all determinants of the required number = (23 + 1 – 1)/(2 – 1) × (31 + 1 – 1)/(3 – 1) = 60

What space the typical Factors the 24 and 21?

Since, the components of 24 space 1, 2, 3, 4, 6, 8, 12, 24 and also the components of 21 room 1, 3, 7, 21.Hence, <1, 3> space the common factors that 24 and 21.