LCM that 15 and 25 is the the smallest number amongst all typical multiples that 15 and 25. The first couple of multiples that 15 and 25 room (15, 30, 45, 60, 75, . . . ) and also (25, 50, 75, 100, 125, 150, 175, . . . ) respectively. There space 3 frequently used methods to uncover LCM the 15 and also 25 - by listing multiples, by department method, and also by element factorization.

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1.LCM that 15 and 25
2.List of Methods
3.Solved Examples
4.FAQs

Answer: LCM that 15 and also 25 is 75.

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Explanation:

The LCM of 2 non-zero integers, x(15) and y(25), is the smallest positive integer m(75) the is divisible by both x(15) and y(25) without any remainder.


The methods to discover the LCM that 15 and 25 are described below.

By element Factorization MethodBy Listing MultiplesBy department Method

LCM the 15 and 25 by prime Factorization

Prime factorization of 15 and also 25 is (3 × 5) = 31 × 51 and (5 × 5) = 52 respectively. LCM that 15 and also 25 can be obtained by multiply prime factors raised to your respective highest possible power, i.e. 31 × 52 = 75.Hence, the LCM of 15 and 25 by element factorization is 75.

LCM the 15 and 25 through Listing Multiples

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To calculate the LCM of 15 and 25 through listing the end the typical multiples, we deserve to follow the given listed below steps:

Step 1: list a couple of multiples that 15 (15, 30, 45, 60, 75, . . . ) and 25 (25, 50, 75, 100, 125, 150, 175, . . . . )Step 2: The typical multiples native the multiples that 15 and 25 are 75, 150, . . .Step 3: The smallest common multiple the 15 and 25 is 75.

∴ The least usual multiple that 15 and also 25 = 75.

LCM the 15 and also 25 by department Method

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To calculation the LCM that 15 and 25 by the division method, we will certainly divide the numbers(15, 25) by your prime components (preferably common). The product of this divisors offers the LCM that 15 and also 25.

Step 3: continue the actions until just 1s are left in the critical row.

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The LCM of 15 and also 25 is the product of every prime number on the left, i.e. LCM(15, 25) by department method = 3 × 5 × 5 = 75.