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if 50.0 ml of a 1.00 M HCl solution and also 45.0 ml that a 1.00 M NaOH solution room combined, which reagrebab.nett is limiting?
The answer to this question would be: NaOH solution Limiting reagrebab.nett is the reagrebab.nett that totally consumed in the reaction. Come answer this question you need to know the equation because that the chemical reaction. The equation would be:HCl + NAOH = H2O + NAClAll the the coefficirebab.nett in the reaction is 1, which typical 1 HCl will certainly react to 1 NaOH. In this question, the concrebab.nettration the HCl and NaOH is same so the lot of the molecule have the right to be reflected by the volume. NaOH has lower volume compared to HCl so it is clear the NaOH will certainly be entirely consumed in this reaction.
3 0
1 year ago

Draw the framework of 1-ethyl-2,2-dimethylcyclohexane
bogdanovich <222>
The structure is in the attached photo. I’ve drawn the compound and also it’s skeletal compound but they are of the exact same molecule.
4 0
1 year ago

The half-life the carbon-14 is 5,730 years. A fossil that is 22,920 years old would have what lot of the common proportion the
scoray <572>

Answer : The amount of the common proportion that carbon-14 come carbon-12 is, 1.07

Explanation :

Half-life = 5730 years

First we need to calculate the rate constant, we usage the formula :

Now we have to calculate the moment passed.

Expression because that rate regulation for very first order kinetics is givrebab.net by:

where,

k = rate continuous =

t = time pass by the sample = 22920 years

a = let initial amount of the reactant = 100

a - x = lot left after ~ decay process = ?

Now placed all the givrebab.net values in above equation, us get

Now we have to calculate the quantity of the common proportion of carbon-14 to carbon-12.

Thus, the lot of the normal proportion that carbon-14 come carbon-12 is, 1.07

5 0
10 month ago

Ions are charged particles. Therefore, ions must constantly have and unequal number of
Kitty <74>
Atoms in elemrebab.nett that the regular table
6 0
1 year ago
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