Google #"temperatura assoluta............"# or #"the Kelvin Scale"#. Friend might already have come throughout this scale.


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The temperature in ~ which the movement of corpuscle theoretically end is #0^0A# or absolute zero, pure #0^0# is the an interpretation of #0^0# on the Kelvin and Rankine temperature scales.

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Absolute zero computes to #-459.67^0F#, i m sorry is also #-273.15^0C.#

At this temperature, both the enthalpy (heat content) and entropy (state the randomness or disorder) approach zero. Effectively, the molecule of the gas room slowing down towards being motionless.

Absolute zero also describes a gas getting to a temperature indigenous which no an ext heat can be removed. Experiments have presented that molecules proceed to vibrate at pure zero.

There are much more thoughts ~ above this subject here:https://www.thoughtco.com/what-is-absolute-zero-604287


Answer attach
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Truong-Son N.
Jul 6, 2017

#"0 K"#, kelvin. However that is no strictly true, together all molecules vibrate at #"0 K"# at your zero-point energy, #1/2 hnu#.

ATOMIC activity AT 0 K

In regards to atoms, yes, the activity of particles will stop at #"0 K"#, or #-"273.15"^
"C"#, since average atom kinetic energy (which for atoms is completely translational) counts on the temperature and also any intermolecular pressures present.

When we consider non-interacting atoms in the classic limit, the equipartition theorem offers for the average per-particle kinetic energy:

#> -= K_(avg,"trans")/N = 3/2 k_BT#, in #"J/particle"#

where the #3# originates from the three cartesian direction (#x,y,z#), #N# is the number of particles, #k_B# is the Boltzmann constant, and also #T# is the temperature in #"K"#.

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MOLECULAR movement AT 0 K

Molecules, top top the other hand, have actually chemical bonds, i m sorry obviously way they have the right to stretch and/or bend. To a first-order approximation, neglecting rotation in ~ #"0 K"# (which is entirely valid), they deserve to be modeled through the simple harmonic oscillator system, through energy

#E_(upsilon) = hnu(upsilon + 1/2) = ℏ omega (upsilon + 1/2)#,

where #upsilon# is the vibrational quantum number, #h# is Planck"s constant, and also #nu# is the basic vibrational frequency in #"s"^(-1)#.

#omega# is the angular frequency, or #2pinu#, and #ℏ = h//2pi# is the diminished Planck"s constant.

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At #"0 K"#, every little thing is in its floor state, and also the vibrational floor state has #upsilon = 0#, so