We’re gift asked tocalculate the mass of barium sulfate (BaSO4)formed in the reaction of100.0 mL of 0.100 M BaCl2 solution and also 100.0 mL the 0.100 M Fe2(SO4)3.

You are watching: The molar mass of barium sulfate is

For this problem, we should do the complying with steps:

Step 1:Determine the commodities of the reaction.

Step 2:Write and also balance a chemical equation because that the given reaction.

Step 3:Determine the limiting reactant and also calculate the mass of BaSO4 produced.

Step 1:Since BaCl2 and Fe2(SO4)3 areionic compounds, they form ions as soon as dissociating in water.The dissociation of the two compounds is as follows:

For BaCl2:

The chloride ion, Cl–, has actually a fee of–1. Barium is from team 2 for this reason it has actually a charge of+2:

BaCl2(aq)⇌Ba2+(aq) + 2Cl–(aq)

For Fe2(SO4)3:

The sulfate ion, SO42–, has actually a fee of–2. Iron then has a fee of+3:

Fe2(SO4)3(aq)⇌2 Fe3+(aq) + 3SO42–(aq)

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Problem Details

What mass of barium sulfate can be produced when 100.0 mL of a 0.100-M solution of barium chloride is combined with 100.0 mL the a 0.100-M systems of iron(III) sulfate?

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