Area of kite is the space enclosed by a kite. A kite is a quadrilateral in which two pairs of surrounding sides space equal. The aspects of a kite room its 4 angles, its 4 sides, and 2 diagonals. In this article, us will focus on the area the a kite and also its formula.

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1.What Is the Area the a Kite?
2.Area the a dragon Formula
3.Derivation the the Area of dragon Formula
4.FAQ's on Area the a Kite

The area the a kite have the right to be identified as the quantity of an are enclosed or included by a kite in a two-dimensional plane. Like a square, and also a rhombus, a kite does not have all four sides equal. The area that a kite is always expressed in terms of units2 for example, in2, cm2, m2, etc. Let us learn about the area that a kite formula in our next section.

The area of a dragon is fifty percent the product that the lengths that its diagonals. The formula to identify the area of a dragon is: Area = (dfrac12 imes d_1 imes d_2). Here (d_1) and also (d_2) room long and also short diagonals of a kite.The area of kite ABCD given below is ½ × AC × BD.


BD = lengthy diagonal and AC = short diagonal

Consider a dragon ABCD as presented above.

Assume the lengths of the diagonals of ABCD to be AC = p, BD = q

We understand that the longer diagonal the a dragon bisects the shorter diagonal at right angles, i.e., BD bisects AC and also ∠AOB = 90°, ∠BOC = 90°.


AO = OC = AC/2 = p/2

Area of kite ABCD = Area that ΔABD + Area that ΔBCD...(1)

We understand that,

Area of a triangle = ½ × basic × Height

Now, we will certainly calculate the areas of triangle ABD and BCD

Area the ΔABD = ½ × AO × BD = ½ × p/2 × q = (pq)/4

Area the ΔBCD = ½ × OC × BD = ½ × p/2 × q = (pq)/4

Therefore, utilizing (1)

Area of dragon ABCD = (pq)/4 + (pq)/4= (pq)/2Substituting the worths of p and qArea of a dragon = ½ × AC × BD

Important Notes

A kite has two bag of surrounding equal sides.

Example 1: four friends room flying kites the the very same size in a park. The lengths of diagonals of every kite space 12 in and also 15 in. Recognize the amount of locations of all the four kites.


Lengths that diagonals are:

(d_1) =12in

(d_2) =15in

The area that each dragon is:

A = (dfrac12 imes d_1 imes d_2)= ½ × 12 × 15= 90 in2

Since each dragon is of the exact same size, therefore the full area of every the four kites is 4 × 90 = 360in2.Therefore the area that the four kites is 360in2

Example 2: Kate wants to give a kite-shaped chocolate box to her friend. She wants to paste a picture of herself with her friend to cover the optimal of the box. Identify the area the the peak of the box if the diagonals the the lid that the box space 9 in and 12 in.

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(d_1) =9in

(d_2) =12in

Since package is kite-shaped, thus the area that the optimal of package is:

A = (dfrac12 imes d_1 imes d_2)= ½ × 9 × 12Therefore, the area of the optimal of the box is 54in2

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