ns was analysis this link and I never ever saw a definite answer. One would certainly think if you have 1000 pounds of water, and you froze it and also weight the you would certainly still have the exact same 1000 pounds that water as soon as weighed in ~ sea level. Even though over there is much less movement, right?



For all practical purposes the weight will stay 1000 pounds when you frozen it. In concept the fixed of the water will minimize somewhat v cooling because it will contain less energy when frozen, yet the effect would be completely negligible.

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Although the weight will certainly be the same, water broadens in volume by about a tenth together it freezes (which is why, because that example, pipes to explode in icy weather). Because it is therefore less dense, your frozen block the 1000 pounds of ice will certainly float on water, however that is since its volume has expanded on freezing and not due to the fact that its weight has actually reduced.

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edited Oct 16 "19 in ~ 13:13
answered Oct 16 "19 at 6:36

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Depends on exactly how you are specifying "weight".

If you median weight as in the vector or scalar the the gravity exhilaration on an object, Marco"s price is what girlfriend want.

There is a third meaning of weight. This is basically "what a scale measures". This meaning also fits through how world typically endure the impacts of weight.

If we usage that definition, then once standing top top Earth, you could say her weight is what is countered by the normal pressure of the ground. Through this definition, astronauts in orbit are also "weightless", even though castle still have actually mass, and gravity exhilaration on them.

Now, when you freeze the water, the mass continues to be the same (so the downward force $mg$ is the same); but the upwards buoyant pressure from the waiting increases, because of the enhanced volume. Due to the fact that the mass stays the same and buoyancy increases, this means the network downward pressure of the ice cream block will reduce, and therefore it"s "weight" as measured through a scale would decrease.

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In the context of the Quora question, ns think this third an interpretation of load is the many relevant; since it is the easiest means to measure weight, and also is commonly what a layperson thinks of when they think about "how much does this object weigh?". This is why people will say freeze water will reduce it"s weight.

If it were weighted in a vacuum, friend wouldn"t intend to watch a detectable adjust in weight because of freezing. Yet vacuum problems aren"t the common human experience, and also most civilization don"t have access to a vacuum chamber through a range in it.