Answer: every squares space rectangles but all rectangles can’t it is in squares, for this reason this declare is false.

(b) all kites room rhombuses.

You are watching: All squares are rhombuses true or false

Answer: every rhombuses room kites but all kites can’t be rhombus.

(c) every rhombuses are parallelograms

Answer: True

(d) all rhombuses space kites.

Answer: True

(e) every squares room rhombuses and likewise rectangles

Answer: True; squares fulfill all criteria of gift a rectangle since all angle are ideal angle and also opposite sides room equal. Similarly, they meet all criteria of a rhombus, together all sides are equal and also their diagonals bisect each other.

(f) every parallelograms room trapeziums.

Answer: False; all trapeziums space parallelograms, yet all parallelograms can’t be trapezoid.

(g) all squares space not parallelograms.

Answer: False; all squares space parallelograms

(h) all squares room trapeziums.

Answer: True

Question 2: identify all the quadrilaterals the have.

(a) four sides the equal size (b) 4 right angles

Answer: (a) If all 4 sides are equal then it deserve to be one of two people a square or a rhombus.(b) All 4 right angles make it one of two people a rectangle or a square.

Question 3: define how a square is.(i) a quadrilateral (ii) a parallel (iii) a rhombus (iv) a rectangle

Answer: (i) Having four sides provides it a quadrilateral(ii) opposite sides are parallel so it is a parallelogram(iii) Diagonals bisect each various other so that is a rhombus(iv) the contrary sides room equal and also angles are best angles so that is a rectangle.

Question 4: surname the quadrilaterals who diagonals.(i) bisect each other (ii) room perpendicular bisectors of each other (iii) room equal

Answer: Rhombus; because, in a square or rectangle diagonals don’t crossing at best angles.

Question 5: define why a rectangle is a convex quadrilateral.

Answer: Both diagonals lie in that interior, so the is a convex quadrilateral.

Question 6: abc is a right-angled triangle and also O is the mid allude of the side opposite to the appropriate angle. Explain why O is equidistant from A, B and also C.

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Answer: If we prolong BO to D, we acquire a rectangle ABCD. Currently AC and BD space diagonals that the rectangle. In a rectangle diagonals are equal and also bisect each other.So, AC = BDAO = OCBO = ODAnd AO = OC = BO = ODSo, it is clear the O is equidistant from A, B and C.